login
The OEIS is supported by the many generous donors to the OEIS Foundation.

 

Logo
Hints
(Greetings from The On-Line Encyclopedia of Integer Sequences!)
A118487 Least number of squares that add up to Lucas numbers L(n). 1
2, 1, 3, 1, 4, 3, 2, 2, 4, 3, 3, 4, 3, 2, 3, 3, 4, 3, 3, 2, 4, 4, 3, 4, 3, 3, 3, 3, 4, 3, 2, 2, 4, 3, 3, 4, 3, 2, 3, 3, 4, 3, 3, 2, 4, 4, 3, 4, 3, 2, 3, 3, 4, 3, 3, 3, 4, 3, 3, 4, 3, 2, 3, 3, 4, 3, 3, 2, 4, 4, 3, 4, 3, 2, 3, 3, 4, 3, 2, 2, 4, 3, 3, 4, 3, 3, 3, 3, 4, 3, 3, 2, 4, 4, 3, 4, 3, 3, 3, 3, 4 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,1
COMMENTS
By the "Four Squares theorem", a(n) <= 4. Any positive integer not of the form 4^k(8m+7) is the sum 3 or fewer squares. See also: A000032 Lucas numbers. See also: A103266 Minimal number of squares needed to sum to Fibonacci(n+1). See also: A000045 Fibonacci numbers: F(n) = F(n-1) + F(n-2), F(0) = 0, F(1) = 1, F(2) = 1, ... See also: A002828 Least number of squares that add up to n.
REFERENCES
Hardy and Wright, An Introduction to the Theory of Numbers, Fourth Ed., Oxford, Section 20.10.
LINKS
FORMULA
a(n) = A002828(A000032(n)).
EXAMPLE
a(4) = 4 because L(4) = 7 = 2^2 + 2^2 + 1^1 + 1^1 is the minimum representation as sum of squares, in this case of 4 squares.
a(20) = 4 because L(20) = 15127 = 74^2 + 73^2 + 59^2 + 29^2.
a(30) = 2 because L(30) = 1860498 = 1077^2 + 837^2.
a(100) = 4 because L(100) = 16930663951^2 + 16706810102^2 + 13499760391^2 + 6637953271^2.
CROSSREFS
Sequence in context: A094522 A233204 A308058 * A241006 A249148 A091420
KEYWORD
easy,nonn
AUTHOR
Jonathan Vos Post, May 16 2006
STATUS
approved

Lookup | Welcome | Wiki | Register | Music | Plot 2 | Demos | Index | Browse | More | WebCam
Contribute new seq. or comment | Format | Style Sheet | Transforms | Superseeker | Recents
The OEIS Community | Maintained by The OEIS Foundation Inc.

License Agreements, Terms of Use, Privacy Policy. .

Last modified April 19 04:35 EDT 2024. Contains 371782 sequences. (Running on oeis4.)