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A118457
Table of partitions of n into distinct parts, in Mathematica ordering.
20
1, 2, 3, 2, 1, 4, 3, 1, 5, 4, 1, 3, 2, 6, 5, 1, 4, 2, 3, 2, 1, 7, 6, 1, 5, 2, 4, 3, 4, 2, 1, 8, 7, 1, 6, 2, 5, 3, 5, 2, 1, 4, 3, 1, 9, 8, 1, 7, 2, 6, 3, 6, 2, 1, 5, 4, 5, 3, 1, 4, 3, 2, 10, 9, 1, 8, 2, 7, 3, 7, 2, 1, 6, 4, 6, 3, 1, 5, 4, 1, 5, 3, 2, 4, 3, 2, 1, 11, 10, 1, 9, 2, 8, 3, 8, 2, 1, 7, 4, 7, 3, 1, 6, 5
OFFSET
1,2
COMMENTS
Reverse lexicographic order where the partitions are reprepresented as (weakly) decreasing lists of parts. [Joerg Arndt, Jan 25 2013]
LINKS
EXAMPLE
The partitions of 5 into distinct parts are [5], [4,1] and [3,2], so row 5 is 5,4,1,3,2.
1;
2;
3; 2,1;
4; 3,1;
5; 4,1; 3,2;
6; 5,1; 4,2; 3,2,1;
7; 6,1; 5,2; 4,3; 4,2,1;
8; 7,1; 6,2; 5,3; 5,2,1; 4,3,1;
9; 8,1; 7,2; 6,3; 6,2,1; 5,4; 5,3,1; 4,3,2;
10; 9,1; 8,2; 7,3; 7,2,1; 6,4; 6,3,1; 5,4,1; 5,3,2; 4,3,2,1;
11; 10,1; 9,2; 8,3; 8,2,1; 7,4; 7,3,1; 6,5; 6,4,1; 6,3,2; 5,4,2; 5,3,2,1;
MATHEMATICA
d[n_] := Select[IntegerPartitions[n], Max[Length /@ Split@ #] == 1 &]; Flatten[Table[d[n], {n, 15}]] (* Clark Kimberling, Mar 11 2012 *)
PROG
(SageMath)
def StrictPartitions(n): return [partition for partition in Partitions(n) if Set(partition.to_exp()).issubset(Set([0, 1]))]
def A118457row(n): return [p for parts in StrictPartitions(n) for p in parts]
for n in (1..9): print(A118457row(n)) # Peter Luschny, Apr 11 2020
CROSSREFS
Cf. A026793, A118459 (partition lengths), A015723 (total row lengths), A080577, A000009, A246688.
Sequence in context: A214573 A344090 A344092 * A319247 A343180 A129773
KEYWORD
nonn,look,tabf
AUTHOR
STATUS
approved