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Eigenvector of triangle A105070, where A105070(n,k) = 2^k*C(n+1,2*k+1) for 0<=k<=[n/2], n>=0.
2

%I #3 Mar 30 2012 18:36:57

%S 1,2,7,20,73,254,895,3080,10801,38426,138775,504284,1838137,6705494,

%T 24464719,89204624,324981985,1183034546,4305313447,15672486692,

%U 57100841641,208309692974,761141694367,2785955603096,10215141094417

%N Eigenvector of triangle A105070, where A105070(n,k) = 2^k*C(n+1,2*k+1) for 0<=k<=[n/2], n>=0.

%C Self-convolution of A118398, which is also an eigenvector of the triangle defined by T(n,k) = 2^k*C(n,2*k).

%F Eigenvector: a(n) = Sum_{k=0..[n/2]} 2^k*C(n+1,2*k+1)*a(k) for n>=0, with a(0)=1. O.g.f. A(x) satisfies: A(x/(1+x))/(1+x)^2 = A(2*x^2).

%e a(7) = Sum_{k=0..[7/2]} A105070(7,k)*a(k) =

%e 8*(1) + 112*(2) + 224*(7) + 64*(20) = 3080.

%o (PARI) a(n)=if(n==0,1,sum(k=0,n\2,2^k*binomial(n+1,2*k+1)*a(k)))

%Y Cf. A105070 (triangle), A118398 (A(x)^(1/2)).

%K eigen,nonn

%O 0,2

%A _Paul D. Hanna_, May 08 2006