login
a(n) = x for which abs(x^x-n!) is minimal.
3

%I #3 Oct 12 2013 15:18:07

%S 1,1,1,2,3,3,4,5,6,6,7,8,9,10,10,11,12,13,14,14,15,16,17,18,18,19,20,

%T 21,22,22,23,24,25,26,27,27,28,29,30,31,32,32,33,34,35,36,37,37,38,39,

%U 40,41,42,42,43,44,45,46,47,47,48,49,50,51,52,52,53,54,55,56,57,57,58,59

%N a(n) = x for which abs(x^x-n!) is minimal.

%e 3! = 6, the closest x^x can get to 6 is 2^2, so a(3) = 2

%Y Cf. A118167, A118170.

%K easy,nonn

%O 0,4

%A _Olaf Voß_, Apr 13 2006