%I #2 Mar 30 2012 18:59:14
%S 1,11,91,1001,11011,91091,999001,10989011,90909091,1000000001,
%T 11000000011,91000000091,1001000001001,11011000011011,91091000091091,
%U 999001000999001,10989011010989011,90909091090909091,999999999000000001
%N Legendre-binomial transform of 10^n for p=3.
%F a(n)=sum{k=0..n, L(C(n,k)/3)*10^k} where L(j/p) is the Legendre symbol of j and p.
%K easy,nonn
%O 0,2
%A _Paul Barry_, Apr 06 2006