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%I #18 Aug 05 2021 16:48:47
%S 66,227,903,17574,40102,462260,5930999
%N Numbers n such that the counts of 0's, 1's and 2's are the same in the ternary expansion of 2^n.
%e 2^66 = {2, 0, 0, 0, 1, 2, 1, 2, 1, 0, 2, 1, 1, 2, 1, 0, 2, 1, 1, 2, 1, 0, 2, 1, 2, 2, 2, 1, 0, 0, 0, 2, 0, 0, 2, 0, 1, 0, 1, 2, 0, 1}
%e Count of 1 = count of 2 = count of 0 = 14, so 66 is member
%e Occurrences of digits 0,1,2 in 2^n:
%e {n, {#0,#1,#2}}
%e {66,{14,14,14}}
%e {227,{48,48,48}}
%e {903,{190,190,190}}
%e {17574,{3696,3696,3696}}
%e {40102,{8434,8434,8434}}
%e {462260,{97218,97218,97218}}. [_Willy Van den Driessche_, Jul 21 2011]
%t Do[If[DigitCount[2^n,3,0]==DigitCount[2^n,3,1]==DigitCount[2^n,3,2],Print[n]],{n,1,60000}]
%t Select[Range[41000],Length[Union[DigitCount[2^#,3,{0,1,2}]]]==1&] (* The program generates the first 5 terms of the sequence. To generate more, increase the Range constant, but the program may take a long time to run. *) (* _Harvey P. Dale_, Aug 05 2021 *)
%K nonn
%O 1,1
%A Mohammed Bouayoun (Mohammed.bouayoun(AT)sanef.com), Apr 24 2006
%E a(6)=462260 added by _Willy Van den Driessche_, Jul 21 2011.
%E a(7) from _Donovan Johnson_, Jul 25 2011
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