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a(n) = (n^3 - 1)^3.
0

%I #14 May 15 2019 06:02:36

%S 0,343,17576,250047,1906624,9938375,40001688,133432831,385828352,

%T 997002999,2352637000,5150827583,10590025536,20638466407,38409197624,

%U 68669157375,118515478528,198257271191,322546580712,511808023999

%N a(n) = (n^3 - 1)^3.

%C Cubes a(1-1),a(8-1),a(27-1),a(64-1),...

%F a(n) = n^9 - 3n^6 + 3n^3 - 1.

%F G.f.: (x^9-2*x^8+694*x^7+14902*x^6+87160*x^5+155914*x^4+89722*x^3+14146*x^2+ 343*x)/(x-1)^10. - _Harvey P. Dale_, Mar 25 2013 [corrected by _Georg Fischer_, May 15 2019]

%F a(n) = A000578(A068601(n)). - _Michel Marcus_, May 15 2019

%t (Range[20]^3-1)^3 (* _Harvey P. Dale_, Mar 25 2013 *)

%Y Cf. A000578 (n^3), A068601 (n^3-1).

%K nonn,easy

%O 1,2

%A Luc Stevens (lms022(AT)yahoo.com), Apr 21 2006

%E Edited and corrected by _Franklin T. Adams-Watters_, Apr 26 2006