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A116951 Let M = {{0, 1}, {1/3, 2}}; w[1] = {0, 1}; w[n] = M.w[n - 1]; then a(n) = w[n][[1]]*3^Floor[2*(n - 1)/3] 0

%I #5 Mar 30 2012 17:34:20

%S 0,1,6,39,84,543,3510,7563,48888,316017,680922,4401549,28452060,

%T 61305669,396286074,2561633451,5519552976,35678951307,230632366770,

%U 496943684847,3212294475852,20764597909653,44741490295158

%N Let M = {{0, 1}, {1/3, 2}}; w[1] = {0, 1}; w[n] = M.w[n - 1]; then a(n) = w[n][[1]]*3^Floor[2*(n - 1)/3]

%t M = {{0, 1}, {1/3, 2}}; w[1] = {0, 1}; w[n_] := w[n] = M.w[n - 1]; a0 = Table[w[n][[1]]*3^Floor[2*(n - 1)/3], {n, 1, 25}]

%K nonn

%O 0,3

%A _Roger L. Bagula_, Apr 03 2006

%E Edited by _N. J. A. Sloane_, May 04 2006

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Last modified August 27 11:42 EDT 2024. Contains 375468 sequences. (Running on oeis4.)