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Numbers n such that sigma(n)=7*reversal(n).
1

%I #8 Oct 28 2012 04:42:38

%S 63301,651001,6967932,2158803990,88858402692

%N Numbers n such that sigma(n)=7*reversal(n).

%C a(6) > 10^12. - _Giovanni Resta_, Oct 28 2012

%e 2158803990 is in the sequence because sigma(2158803990)

%e =6951619584=7*993088512=7*reversal(2158803990).

%Y Cf. A069216, A105324, A114928.

%K base,more,nonn

%O 1,1

%A _Farideh Firoozbakht_, Feb 12 2006

%E a(5) from _Donovan Johnson_, Dec 21 2008