A114844 - OEIS

%I #24 Apr 11 2021 04:54:33

%S 9,10,14,15,40,43046761,43046763,44726379,44726404,44732965,44733590,

%T 44766358,432186847,432186848,432193409,432193652,432193656,432193683,

%U 432226451,432226515,432273171,432273172,432273208,432338744,432340931

%N Sum of first n digits of Pi to digit-wise power of first n digits of e.

%C The 331st digit of Pi and the 331st digit of e are both 0, so to generate any additional terms of the sequence beyond 330 terms one would have to define 0^0 to be either 0 or 1. - _Harvey P. Dale_, Aug 05 2014

%H Harvey P. Dale, <a href="/A114844/b114844.txt">Table of n, a(n) for n = 1..300</a>

%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/PiDigits.html">Pi Digits</a>.

%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/e.html">e</a>.

%F a(n) = Sum_{i=1..n} A000796(i)^A001113(i).

%e Since Pi =

%e 3.1415926535897932384626433832795028841971693993751058209749445923078164062...

%e and e =

%e 2.71828182845904523536028747135266249775724709369995957496696762772407663...

%e we have:

%e a(1) = 9 = 3^2.

%e a(2) = 10 = 3^2 + 1^7.

%e a(3) = 14 = 3^2 + 1^7 + 4^1.

%e a(4) = 15 = 3^2 + 1^7 + 4^1 + 1^8.

%e a(5) = 40 = 3^2 + 1^7 + 4^1 + 1^8 + 5^2.

%e a(6) = 43046761 = 3^2 + 1^7 + 4^1 + 1^8 + 5^2 + 9^8.

%t With[{nn=30},Accumulate[RealDigits[Pi,10,nn][[1]]^RealDigits[E,10,nn] [[1]]]] (* _Harvey P. Dale_, Aug 05 2014 *)

%Y Cf. A000796, A001113, A039661, A059850, A114605.

%K base,easy,nonn

%O 1,1

%A _Jonathan Vos Post_, Feb 19 2006