OFFSET
0,3
COMMENTS
Row n has 1+floor(n/3) terms.
FORMULA
G.f.: 1/(1+z^3-tz^3-zC), where C=[1-sqrt(1-4z)]/(2z) is the Catalan function.
Sum_{k=0..floor(n/3)} k*T(n,k) = Catalan(n-2) (n>=3; A000108).
EXAMPLE
T(4,1)=2 because we have UD(UUUDDD) and (UUUDDD)UD (or UD(UUDUDD) and (UUDUDD)UD). The 3-bridges are shown between parentheses.
Triangle starts:
1;
1;
2;
4, 1;
12, 2;
37, 5;
119, 12, 1;
390, 36, 3;
1307, 114, 9;
MAPLE
C:=(1-sqrt(1-4*z))/2/z: G:=1/(1-z*C+z^3-t*z^3): Gser:=simplify(series(G, z=0, 20)): P[0]:=1: for n from 1 to 17 do P[n]:=coeff(Gser, z^n) od: for n from 0 to 17 do seq(coeff(t*P[n], t^j), j=1..1+floor(n/3)) od; # yields sequence in triangular form
CROSSREFS
KEYWORD
nonn,tabf
AUTHOR
Emeric Deutsch, Dec 04 2005
STATUS
approved
