%I #10 Nov 13 2014 12:02:01
%S 1,0,1,0,1,1,0,1,1,0,1,0,1,1,0,1,1,1,0,1,0,1,1,0,1,1,0,1,0,1,1,0,1,1,
%T 1,1,0,1,0,1,1,0,1,1,0,1,0,1,1,0,1,1,1,1,0,1,0,1,1,0,1,1,0,1,0,1,1,0,
%U 1,1,1,0,1,0,1,1,0,1,1,0,1,0,1,1,0,1,1,1,1,0,1,0,1,1,0,1,1,0,1,0,1,1,0,1,1
%N s(1)={1}. s(2)={1,0}. If a(n) = 0, s(n+2) = s(n+1) U s(n) U {1}. If a(n) = 1, s(n+2) = s(n+1) U s(n+1) U {1}. (U represents concatenation of finite sequences.) {a(n)} is the limit of {s(n)} as n -> infinity.
%C Number of terms in s(n) is A112361(n).
%e s(3) = {1,0,1,0,1}, s(4) = {1,0,1,0,1,1,0,1}, s(5) = {1,0,1,0,1,1,0,1,1,0,1,0,1,1,0,1,1}
%Y Cf. A114482, A062318, A112361.
%K easy,nonn
%O 1,1
%A _Leroy Quet_, Nov 30 2005
%E More terms from _Joshua Zucker_, Jul 27 2006