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Records in 3-almost prime gaps ordered by merit.
0

%I #12 Jan 21 2025 23:45:37

%S 4,6,12,58,83

%N Records in 3-almost prime gaps ordered by merit.

%F a(n) = records in A114403(n)/log_10(A014612(n)) = records in (A014612(n+1) - A014612(n))/log_10(A014612(n)).

%e Records defined in terms of A114403 and A014612:

%e n A114403(n) A114403(n)/log_10(A014612(n))

%e = ========== =============================

%e 1 4 4/log_10(8) = 4.42923746

%e 2 6 6/log_10(12) = 5.55977045

%e 3 2 2/log_10(18) = 1.59327954

%e 4 7 7/log_10(20) = 5.38035251

%e 5 1 1/log_10(27) = 0.698634425

%e 6 2 2/log_10(28) = 1.38201907

%e 7 12 12/log_10(30) = 8.12390991

%e ...

%e 19 14 14/log_10(78) = 7.3992072

%Y Cf. A014612, A065516, A111870, A111871, A114403-A114411, A114412-A114422.

%K nonn,more

%O 1,1

%A _Jonathan Vos Post_, Nov 25 2005

%E a(4)-a(5) from _Donovan Johnson_, Feb 17 2010