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Self-convolution 4th power of A113670, where a(n) = A113670(n+1)/(n+1).
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%I #8 Oct 23 2020 06:23:09

%S 1,4,38,556,10745,254700,7100444,226687964,8138624340,324257974800,

%T 14191562670382,676772204063828,34931592000218062,1940427169943222088,

%U 115440543670528170360,7323969420842077029820,493653199877341017573868

%N Self-convolution 4th power of A113670, where a(n) = A113670(n+1)/(n+1).

%H Vaclav Kotesovec, <a href="/A113664/b113664.txt">Table of n, a(n) for n = 0..360</a>

%F G.f. satisfies: A(x) = (1 + x*d/dx[x*A(x)] )^4.

%F a(n) ~ c * 4^n * n! * n^(3/4), where c = 0.71282302257258522141135342... - _Vaclav Kotesovec_, Oct 23 2020

%o (PARI) {a(n)=local(A=1+x*O(x^n));for(i=1,n, A=(1+x*deriv(x*A))^4);polcoeff(A,n,x)}

%Y Cf. A113670, A113662, A113663, A113665, A113666, A113667, A113668.

%K nonn

%O 0,2

%A _Paul D. Hanna_, Nov 04 2005