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Number of highly composite numbers between two consecutive superior highly composite numbers.
1

%I #8 Aug 15 2019 07:26:39

%S 1,0,3,0,2,4,0,8,9,1,3,6,11,12,1,13,7,14,3,14,2,15,16,15,17,7,18,19,4,

%T 12,22,3,22,24,23,25,14,25,25,3,26,26,30,30,11,32,33,19,34,33,34,35,6,

%U 10,35,35,23,4,35,35,36,37,38,36,35

%N Number of highly composite numbers between two consecutive superior highly composite numbers.

%C The SHC numbers are a subset of the HC numbers. Is there a formula for a(n) that depends on the two consecutive SHC numbers A002201(n) and A002201(n+1)?

%H Amiram Eldar, <a href="/A113069/b113069.txt">Table of n, a(n) for n = 1..4252</a> (Calculated from Achim Flammenkamp's List of the first 779,674 highly composite numbers)

%H Achim Flammenkamp, <a href="http://wwwhomes.uni-bielefeld.de/achim/highly.html">Highly Composite Numbers</a>.

%e Example: a(3)=3 because between the SHC numbers 12 and 60 there are three HC numbers: 24, 36 and 48.

%Y Cf. A002182 (highly composite numbers), A002201 (superior highly composite numbers).

%K nonn

%O 1,3

%A _T. D. Noe_, Oct 13 2005