A112974 - OEIS

%I #7 Mar 30 2012 17:22:41

%S 1,0,3,0,2,4,0,4,6,0,2,3,6,8,6,0,10,10,5,2,11,9,10,0,9,10,12,4,13,14,

%T 15,11,6,14,0,12,2,12,11,5,10,11,12,12,12,11,11,13,13,0,15,14,3,14,16,

%U 16,8,16,17,17,19,20,16,14,7,16,2,16,14,15,3,15,15,14,18,0,16,16,16,16,16,14

%N Number of superabundant numbers between two consecutive colossally abundant numbers.

%C The colossally abundant numbers are a subset of the superabundant abundant numbers. Is there a formula for a(n) that depends on the two consecutive colossally abundant numbers A004490(n) and A004490(n+1)?

%H T. D. Noe, <a href="/A112974/b112974.txt">Table of n, a(n) for n=1..10000</a>

%e a(3)=3 because between colossally abundant numbers 12 and 60 there are three superabundant numbers: 24, 36 and 48.

%Y Cf. A004490 (colossally abundant numbers), A004394 (superabundant numbers), A189228 (superabundant numbers that are not colossally abundant).

%K nonn

%O 1,3

%A _T. D. Noe_, Oct 07 2005