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%I #7 Aug 15 2019 07:27:09
%S 1,2,3,20,336,154440,8204716800,5778574175582208000,
%T 43004718293359780142729736192000000,
%U 1300207208378579462193856077468752280037294977727353323520000000
%N a(n) = F(n+1)!/F(n)! where F(n) = n-th Fibonacci number.
%e a(5) = 8!/5! = 336.
%p with(combinat): seq(fibonacci(n+1)!/fibonacci(n)!,n=1..11); # _Emeric Deutsch_, Jul 25 2005
%Y Cf. A060001.
%K easy,nonn
%O 1,2
%A _Amarnath Murthy_, Jul 24 2005
%E More terms from _Emeric Deutsch_, Jul 25 2005
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