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Number of consecutive integers starting with n needed to sum to a perfect power.
2

%I #3 Dec 15 2017 17:36:57

%S 8,3,5,1,9,11,13,1,1,19,3,2,2,27,29,1,33,5,37,9,8,43,5,2,1,3,1,25,57,

%T 59,61,1,65,67,6,1,8,6,11,2,81,83,5,87,9,7,3,95,1,22,27,18,15,107,16,

%U 81,8,10,117,2,121,2,125,1,129,131,19,27,25,139,3,26,145,3,149,18,9,5,157,3

%N Number of consecutive integers starting with n needed to sum to a perfect power.

%e a(5)=9 because 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 = 81 = 3^4, 9 consecutive integers are needed.

%Y Cf. A110233, A108910.

%K easy,nonn

%O 1,1

%A _Jason Earls_, Jul 17 2005