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Start to read the sequence digit by digit and erase the first "1" you encounter, then the first "2", the first "3", etc., until the first "0"; go on from there and erase again the first "1", the first "2", etc., until "0" -- and so on, cyclically until the end of the (infinite) sequence. Concatenate what is left. The result is the concatenation of all integers of the sequence.
1

%I #11 May 01 2021 09:28:19

%S 1,12,13,24,153,627,4819,5031,6223,7445,8617,985900,3112632,4253677,

%T 4849508,16213749,58657980,90031121,324653627,482950316,2737445864,

%U 7985900811,26324153677,489950816253,74958607980900,311213241536274

%N Start to read the sequence digit by digit and erase the first "1" you encounter, then the first "2", the first "3", etc., until the first "0"; go on from there and erase again the first "1", the first "2", etc., until "0" -- and so on, cyclically until the end of the (infinite) sequence. Concatenate what is left. The result is the concatenation of all integers of the sequence.

%C Fractal-like sequence

%e Sequence starts: 1 12 13 24 153 627 4819 5031... Erasing cyclically digits 1 --> 0 gives: . 1. 1. 2. 1.3 .2. 4.1. 5.3. which is the pattern of the sequence itself.

%Y Cf. A108709.

%K base,easy,nonn

%O 1,2

%A _Eric Angelini_, Jun 20 2005