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Start to read the sequence digit by digit and erase the first "1" you encounter, then the first "2", the first "3", etc., until the first "9"; go on from there and erase again the first "1", the first "2", etc., until "9" -- and so on, cyclically until the end of the (infinite) sequence. Concatenate what is left. The result is the concatenation of all integers of the sequence.
1

%I #9 May 01 2021 09:29:11

%S 1,12,13,24,153,627,4819,5132,6324,7546,8789,9511,23324,65362,74879,

%T 514263,847516,879899,5111213,24353627,48695132,63247546,87789951,

%U 124324653,687487951,1263847596,8798995112,13241536274,83951326324

%N Start to read the sequence digit by digit and erase the first "1" you encounter, then the first "2", the first "3", etc., until the first "9"; go on from there and erase again the first "1", the first "2", etc., until "9" -- and so on, cyclically until the end of the (infinite) sequence. Concatenate what is left. The result is the concatenation of all integers of the sequence.

%C Fractal-like sequence.

%e Sequence starts: 1 12 13 24 153 627 4819 5132 ... Erasing cyclically digits 1 --> 9 gives: . 1. 1. 2. 1.3 .2. 4.1. 5.3. which is the pattern of the sequence itself.

%Y Cf. A108710.

%K base,easy,nonn

%O 1,2

%A _Eric Angelini_, Jun 20 2005