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Sum_{i=0..n} binomial(2n+i,2i).
0

%I #7 Apr 12 2018 18:25:23

%S 1,4,26,176,1204,8273,56967,392688,2708322,18683233,128892764,

%T 889172365,6133354976,42300883471,291696384929,2011120962840,

%U 13863370486596,95548230542403,658416136868846,4536321401562529

%N Sum_{i=0..n} binomial(2n+i,2i).

%F a(n) ~ phi^(4*n + 1) / sqrt(5), where phi = A001622 = (1 + sqrt(5))/2 is the golden ratio. - _Vaclav Kotesovec_, Apr 12 2018

%t Table[Sum[Binomial[2n+i,2i],{i,0,n}],{n,0,20}] (* _Harvey P. Dale_, Apr 12 2018 *)

%K nonn

%O 0,2

%A _Ralf Stephan_, Jun 03 2005