OFFSET
1,1
FORMULA
a(1)=2; a(2)=3; n>=3: a(n) = numerator(2*a(n-1)*a(n-2)/(a(n-2)+a(n-1))).
Conjecture: G.f.: x*(2+3*x+12*x^2+8*x^3+8*x^4)/[(1-2*x)*(1+2*x+4*x^2)]. a(3n) = (3/2)*8^n, a(3n+1) = 3*8^n, a(3n+2) = 2*8^n, for n>0. - Ralf Stephan, Dec 01 2010
MATHEMATICA
a[1]=2; a[2]=3; a[n_]:=a[n]=Numerator[HarmonicMean[{a[n-1], a[n-2]}]];
nxt[{a_, b_}]:={b, Numerator[HarmonicMean[{a, b}]]}; Transpose[ NestList[nxt, {2, 3}, 30]][[1]] (* Harvey P. Dale, Jul 25 2013 *)
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Zak Seidov, Jun 10 2005
STATUS
approved