A105932 An eight-symbol substitution on an hypertetrahedron with four symbol connection per vertex.

1, 1, 2, 3, 4, 5, 1, 2, 3, 4, 5, 2, 3, 4, 5, 1, 3, 4, 6, 1, 2, 4, 7, 1, 2, 3, 8, 1, 6, 7, 8, 1, 2, 3, 4, 5, 2, 3, 4, 5, 1, 3, 4, 6, 1, 2, 4, 7, 1, 2, 3, 8, 1, 6, 7, 8, 2, 3, 4, 5, 1, 3, 4, 6, 1, 2, 4, 7, 1, 2, 3, 8, 1, 6, 7, 8, 1, 3, 4, 6, 1, 2, 4, 7, 1, 2, 3, 8, 1, 6, 7, 8, 2, 3, 4, 5, 1, 2, 4, 7, 1, 2, 3, 8, 2

Offset

0,3

Comments

This flow can be visualized in 3d by using a cube's vertices as the substitution for the eight points.

Links

Table of n, a(n) for n=0..104.

Formula

1->{2, 3, 4, 5}, 2->{1, 3, 4, 6}, 3->{1, 2, 4, 7}, 4->{1, 2, 3, 8}, 5->{1, 6, 7, 8}, 6->{2, 5, 7, 8}, 7->{3, 5, 6, 8}, 8->{4, 5, 6, 7}

Mathematica

s[1]={2, 3, 4, 5}; s[2]={1, 3, 4, 6}; s[3]={1, 2, 4, 7}; s[4]={1, 2, 3, 8}; s[5]={1, 6, 7, 8}; s[6]={2, 5, 7, 8}; s[7]={3, 5, 6, 8}; s[8]={4, 5, 6, 7}; t[a_] := Join[a, Flatten[s/@a]]; p[0]={1}; p[1]=t[{1}]; p[n_]:=t[p[n-1]] a=Flatten[Table[p[n], {n, 0, 3}]]

Crossrefs

Sequence in context: A053841 A010884 A339146 * A106652 A338479 A193106

Adjacent sequences: A105929 A105930 A105931 * A105933 A105934 A105935

Keyword

nonn,uned

Author

Roger L. Bagula, Apr 26 2005

Status

approved