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Moebius transform of multiplication table, read by antidiagonals.
2

%I #9 Dec 03 2016 12:17:58

%S 1,1,1,1,-1,1,1,1,1,1,1,1,0,1,1,1,0,-1,-1,0,1,1,1,0,0,0,1,1,1,-1,-1,0,

%T 0,-1,-1,1,1,1,0,-1,0,-1,0,1,1,1,0,-1,0,0,0,0,-1,0,1,1,0,0,-1,0,0,0,

%U -1,0,0,1,1,-1,0,0,0,1,1,0,0,0,-1,1,1,1,0,0,0,-1,0,-1,0,0,0,1,1,1,0,-1,1,0,0,1,1,0,0,1,-1,0,1,1,1,0,-1,0

%N Moebius transform of multiplication table, read by antidiagonals.

%C Rows sum of triangle are A105568. Diagonal sums are A105569.

%F As a table read by antidiagonals, T(n, k) = -mu(k*n);

%F As a number triangle read by rows, T(n, k) = if(k<=n, -mu(k(n-k)), 0).

%e Triangle begins

%e 1;

%e 1, 1;

%e 1, -1, 1;

%e 1, 1, 1, 1;

%e 1, 1, 0, 1, 1;

%e 1, 0, -1, -1, 0, 1;

%Y Cf. A003991.

%K easy,sign,tabl

%O 0,1

%A _Paul Barry_, Apr 14 2005