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%I #6 Mar 12 2014 16:36:47
%S 0,1,1,1,0,1,1,1,1,1,0,1,1,1,1,2,0,1,1,1,1,1,0,1,1,1,1,2,1,1,1,2,1,1,
%T 0,1,1,1,1,2,2,2,1,3,0,1,1,1,1,1,0,1,1,1,1,2,1,1,1,2,1,1,0,1,1,1,1,2,
%U 2,2,1,3,1,1,1,2,2,2,1,3,1,1,1,2,1,1,0,1,1,1,1,2,2,2,1,3,2,2,2,4,3,3,1,4,0
%N Vector triangular array of Fibonacci tensor Markov.
%C This is the triangle form from {6,2,2}. T[n,k,j] levels j: {0, 1, 1, 1} {0, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 2} {0, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 2, 1, 1, 1, 2, 1, 1, 0, 1, 1, 1, 1, 2, 2, 2, 1, 3} {0, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 2, 1, 1, 1, 2, 1, 1, 0, 1, 1, 1, 1, 2, 2, 2, 1, 3, 1, 1, 1, 2, 2, 2, 1, 3, 1, 1, 1, 2, 1, 1, 0, 1, 1, 1, 1, 2, 2, 2, 1, 3, 2, 2, 2, 4, 3, 3, 1, 4}
%F v[n]=M.v[n-1] M={M1, M2} M1={{0, 1}, {1, 0}} M2={{0, 1}, {1, 1}} Selective flattening and expression to get a vector triangle representation =a[n]
%t v[1] = {{0, 1}, {1, 1}} M = {{{0, 1}, {1, 1}}, {{0, 1}, {1, 1}}} v[n_] := v[n] = M.v[n - 1] a = Table[v[n], {n, 1, 6}] Dimensions[a aa = Table[Flatten[Table[Table[a[[n, j]], {j, 1, 2}], {n, 1, m}]], {m, 1, 6}] aout= Flatten[aa]
%K nonn,uned,obsc
%O 1,16
%A _Roger L. Bagula_, Apr 12 2005
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