%I #17 Apr 30 2014 01:30:12
%S 1,3,3,1,3,3,1,3,3,1,3,1,3,3,1,3,3,1,3,3,1,3,1,3,3,1,3,3,1,3,3,1,3,1,
%T 3,3,1,3,3,1,3,3,3,1,3,3,1,3,3,1,3,3,1,3,1,3,3,1,3,3,1,3,3,1,3,1,3,3,
%U 1,3,3,1,3,3,1,3,1,3,3,1,3,3,1,3,3,3,1,3,3,1,3,3,1,3,3,1,3,1,3
%N Consider numbers k such that (A102370(k)-k)/2 = 1; read them mod 4 to get the sequence.
%C Is there a self-contained construction of this two-valued sequence?
%C Sequence appears to have period 43. - _Ralf Stephan_, May 18 2007
%H David Applegate, Benoit Cloitre, Philippe Deléham and N. J. A. Sloane, Sloping binary numbers: a new sequence related to the binary numbers [<a href="http://neilsloane.com/doc/slopey.pdf">pdf</a>, <a href="http://neilsloane.com/doc/slopey.ps">ps</a>], J. Integer Seq. 8 (2005), no. 3, Article 05.3.6, 15 pp.
%e The numbers k are 1, 3, 7, 9, 11, 15, 17, 19, ...
%Y Cf. A102370, A103587.
%K nonn,base
%O 1,2
%A _Benoit Cloitre_ and _Philippe Deléham_, Mar 24 2005