%I #14 Jan 31 2020 15:05:26
%S 1,1,1,1,1,1,1,1,4,1,1,1,2,2,1,5,1,4,1,1,1,1,2,1,1,1,1,1,1,1,1,1,1,1,
%T 1,1,1,1,1,1,1,1,1,1,1,1,14,2,2,2,4,2,2,8,2,2,2,4,2,2,2,1,1,1,1,1,1,1,
%U 1,1,1,1,1,1,1,1,1,13,8,2,2,2,2,2,2,8,2,2,4,4,2,2,2,2,1,5,5,25,5,5,5,5,5,5,25,5,5,5,1,2,2,4,4,4
%N a(n) = gcd(reverse(prime(n)), reverse(prime(n+1))).
%C Greatest common divisor of two consecutive primes after each prime is written backward.
%H Harvey P. Dale, <a href="/A103163/b103163.txt">Table of n, a(n) for n = 1..1000</a>
%F a(n) = gcd(A004087(n), A004087(n+1)).
%e Neither of these common divisors are divisible by 3 or by 10 or by 11.
%p A103163 := proc(n)
%p p := ithprime(n) ;
%p q := nextprime(p) ;
%p igcd(digrev(p),digrev(q)) ;
%p end proc:
%p seq(A103163(n),n=1..114) ; # _R. J. Mathar_, Sep 22 2018
%t rd[x_] :=FromDigits[Reversed[IntegerDigits[x]]]; Table[GCD[rd[Prime[w]], rd[Prime[w+1]]], {w, 1, 1000}]
%t GCD@@#&/@(Partition[IntegerReverse/@Prime[Range[120]],2,1]) (* Requires Mathematica version 10 or later *) (* _Harvey P. Dale_, Jan 31 2020 *)
%Y Cf. A004087, A000040.
%K base,nonn
%O 1,9
%A _Labos Elemer_, Jan 27 2005
%E Edited by _Jon E. Schoenfield_, Oct 26 2019