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%I #24 Nov 19 2022 00:53:45
%S 0,1,2,3,10,11,12,13,20,21,22,26,30,31,33,99,100,101,102,103,110,111,
%T 112,113,120,121,122,130,200,201,202,210,211,212,220,221,260,264,300,
%U 301,307,310,311,330,836,990,1000,1001,1002,1003,1010,1011,1012,1013,1020
%N Numbers that when squared and written backwards give a square again.
%C Contains A002778. - _Robert Israel_, Sep 20 2015
%C Squares of these terms are in A061457. - _Jon E. Schoenfield_, May 17 2022
%H Jon E. Schoenfield, <a href="/A102859/b102859.txt">Table of n, a(n) for n = 1..10000</a>
%H <a href="/index/Sq#sqrev">Index entry for sequences related to reversing digits of squares</a>
%F a(n) = sqrt(A061457(n)). - _Jon E. Schoenfield_, May 17 2022
%e a(7)=12 belongs to the sequence since writing 12^2 = 144 backwards gives 441 = 21^2.
%p rev:= proc(n)
%p local L, Ln, i;
%p L:= convert(n, base, 10);
%p Ln:= nops(L);
%p add(L[i]*10^(Ln-i), i=1..Ln);
%p end proc:
%p select(t -> issqr(rev(t^2)),[$0..10^5]); # _Robert Israel_, Sep 20 2015
%t Select[Range[1000], IntegerQ[Sqrt[FromDigits[Reverse[IntegerDigits[ #^2]]]]] &]
%o (Magma) [n: n in [0..1100] | IsSquare(Seqint(Reverse(Intseq(n^2))))]; // _Vincenzo Librandi_, Sep 21 2015
%o (Python)
%o from itertools import count, islice
%o from sympy import integer_nthroot
%o def A102859_gen(startvalue=0): # generator of terms >= startvalue
%o return filter(lambda n:integer_nthroot(int(str(n**2)[::-1]),2)[1], count(max(startvalue,0)))
%o A102859_list = list(islice(A102859_gen(),30)) # _Chai Wah Wu_, Nov 18 2022
%Y Cf. A002778, A002942.
%Y Cf. A061457 (squares).
%K base,easy,nonn
%O 1,3
%A Sanita Kashcheyeva (sanits(AT)gmail.com), Mar 01 2005
%E 0 inserted by _Jon E. Schoenfield_, Sep 20 2015