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a(n) = 10000*n + 2468.
1

%I #23 Dec 08 2024 12:58:18

%S 2468,12468,22468,32468,42468,52468,62468,72468,82468,92468,102468,

%T 112468,122468,132468,142468,152468,162468,172468,182468,192468,

%U 202468,212468,222468,232468,242468,252468,262468,272468,282468,292468,302468,312468,322468,332468,342468

%N a(n) = 10000*n + 2468.

%H Vincenzo Librandi, <a href="/A102689/b102689.txt">Table of n, a(n) for n = 0..1000</a>

%H Tanya Khovanova, <a href="http://www.tanyakhovanova.com/RecursiveSequences/RecursiveSequences.html">Recursive Sequences</a>.

%H <a href="/index/Rec#order_02">Index entries for linear recurrences with constant coefficients</a>, signature (2,-1).

%F From _Elmo R. Oliveira_, Dec 07 2024: (Start)

%F G.f.: 4*(617 + 1883*x)/(1 - x)^2.

%F E.g.f.: 4*exp(x)*(617 + 2500*x).

%F a(n) = 2*a(n-1) - a(n-2) for n >= 2. (End)

%t Table[10000*n+2468,{n,0,50}] (* _Harvey P. Dale_, Feb 24 2015 *)

%t LinearRecurrence[{2, -1}, {2468, 12468}, 50] (* _Vincenzo Librandi_, Aug 16 2017 *)

%o (Magma) [10000*n+2468: n in [0..50]]; // _Vincenzo Librandi_, Aug 16 2017

%K easy,nonn,less,changed

%O 0,1

%A _Giovanni Teofilatto_, Feb 25 2005