A102352 - OEIS

%I #17 Jun 03 2013 03:35:42

%S 2,3,4,5,6,7,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,

%T 28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,

%U 51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69,70,71,72,73,74

%N Numbers n such that n^3 can be partitioned into n primes such that n-1 are consecutive primes and the remaining prime is larger than the sum of the n-1 consecutive primes.

%C Indices of nonzero terms in A102706.

%C It appears that this sequence contains all numbers except 1 and 8 - is there a proof?

%e 3 is a member since 3^3 = 27 = 3+5+19, where 3 and 5 are consecutive and 19 > 3+5.

%Y Cf. A102706.

%K easy,nonn

%O 1,1

%A _Giovanni Teofilatto_, Feb 21 2005

%E Edited by _Ray Chandler_ Feb 25 2005