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a(1) = a(2) = 1, a(3) = 9; for n > 3, a(n) = 3*a(n-1) - 3*a(n-2) + 9*a(n-3).
9

%I #61 Sep 08 2022 08:45:16

%S 1,1,9,33,81,225,729,2241,6561,19521,59049,177633,531441,1592865,

%T 4782969,14353281,43046721,129127041,387420489,1162300833,3486784401,

%U 10460235105,31381059609,94143533121,282429536481,847287546561,2541865828329,7625600673633

%N a(1) = a(2) = 1, a(3) = 9; for n > 3, a(n) = 3*a(n-1) - 3*a(n-2) + 9*a(n-3).

%C Alternate terms are powers of 9 (A001019): a(2b+1) = 9^b; b = 0, 1, 2, ...

%C a(n) is the number of solutions to Sum_{i=1..n} x_i^2 == 0 (mod 3) for (x_1, x_2, ..., x_n). - _Jianing Song_, Jul 03 2018

%H Colin Barker, <a href="/A101990/b101990.txt">Table of n, a(n) for n = 1..1000</a>

%H <a href="/index/Rec#order_03">Index entries for linear recurrences with constant coefficients</a>, signature (3,-3,9).

%F a(n) = first term in M^n * [1 0 0]^T, where M = the 3 X 3 matrix [1 0 2 / 2 1 0 / 0 2 1] and T denotes transpose. [Edited by _Michel Marcus_, Dec 20 2019]

%F G.f.: x*(1 - 2*x + 9*x^2)/((1 - 3*x)*(1 + 3*x^2)). - _R. J. Mathar_, Aug 22 2008

%F a(n) = 2^n*n!*[x^n] (exp(3*x/2) + 2*cos(sqrt(3)*x/2))/3. - _Peter Luschny_, Aug 01 2012

%F a(n) = 3^(n/2 - 1)*((-i)^n + i^n + 3^(n/2)) where i = sqrt(-1). - _Colin Barker_, Sep 23 2016

%F From _Jianing Song_, Sep 05 2018: (Start)

%F E.g.f.: 1/3*(exp(3*x) + 2*cos(sqrt(3)*x)) (with a(0) = 1 prepended).

%F a(n) = 3^(n/2 - 1)*(2*cos(n*Pi/2) + 3^(n/2)).

%F a(n) = 3^(n-1) for odd n and 3^(n-1) - 2*(-3)^(n/2-1) for even n.

%F a(n) = a(n-1) + 2*A318610(n-1).

%F a(n) + A318609(n) + A318610(n) = 3^n.

%F (End)

%e a(5) = 81 since M^5 * [1 0 0]^T = [81 90 72]^T.

%e a(5) = 81 = 99 - 27 + 9 = 3*33 - 3*9 + 9*1 = 3*a(4) - 3*a(3) + 9*a(2).

%e a(7) = 729 = 9^3. (let b = 3, then n = 2b+1 = 7; and a(2b+1) = 9^b.

%p seq(`if`( `mod`(n,2)=1, 3^(n-1), 3^(n-1)-2*(-3)^(n/2 -1) ), n = 0..30); # _G. C. Greubel_, Dec 20 2019

%t a[n_]:= a[n]= 3a[n-1] - 3a[n-2] + 9a[n-3]; a[1]= a[2]= 1; a[3]= 9; Table[ a[n], {n, 26}] (* Or *)

%t a[n_] := (MatrixPower[{{1, 0, 2}, {2, 1, 0}, {0, 2, 1}}, n].{{1}, {0}, {0}})[[1, 1]]; Table[ a[n], {n, 26}] (* _Robert G. Wilson v_, Dec 23 2004 *)

%o (Sage)

%o def A101990_list(n) :

%o f = (exp(3*x/2)+2*cos(sqrt(3)*x/2))/3

%o s = f.series(x,n+2)

%o return [(2^i*factorial(i)*s.coefficient(x,i)) for i in (1..n)]

%o A101990_list(26) # _Peter Luschny_, Aug 01 2012

%o (PARI) Vec(x*(1-2*x+9*x^2)/((1-3*x)*(1+3*x^2)) + O(x^40)) \\ _Colin Barker_, Sep 23 2016

%o (PARI) a(n) = ([1, 0, 2 ; 2, 1, 0 ; 0, 2, 1]^n*mattranspose([1, 0, 0]))[1]; \\ _Michel Marcus_, Dec 20 2019

%o (Magma) a:=[1,1,9]; [n le 3 select a[n] else 3*Self(n-1)-3*Self(n-2) + 9*Self(n-3):n in [1..30]]; // _Marius A. Burtea_, Dec 20 2019

%o (GAP) a:=[1,1,9];; for n in [4..30] do a[n]:=3*a[n-1]-3*a[n-2]+9*a[n-3]; od; a; # _G. C. Greubel_, Dec 20 2019

%Y A318609 gives the number of solutions to Sum_{i=1..n} x_i^2 == 1 (mod 3);

%Y A318610 gives the number of solutions to Sum_{i=1..n} x_i^2 == 2 (mod 3).

%K nonn,easy

%O 1,3

%A _Gary W. Adamson_, Dec 23 2004

%E Edited and extended by _Robert G. Wilson v_, Dec 23 2004