%I #3 Mar 30 2012 17:37:42
%S 1,67585,84466,854696
%N Numbers n such that phi(n) is equal to d_1!+d_2!+...+d_k!, where d_1 d_2 ... d_k is the decimal expansion of n.
%e 854696 is in the sequence because phi(854696)=8!+5!+4!+6!+9!+6!.
%t Do[h = IntegerDigits[n]; l = Length[h]; If[EulerPhi[n] == Sum[h[[k]]!, {k, l}], Print[n]], {n, 10000000}]
%Y Cf. A100416.
%K base,fini,full,nonn
%O 1,2
%A _Farideh Firoozbakht_, Dec 12 2004
