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%I #3 Jan 21 2019 19:01:55
%S 3,5,257,340282366920938463463374607431768211457
%N Fermat(Mersenne(x)) = 2^(2^(2^x-1))+1
%C Fermat-Mersenne numbers.
%e F(M(0))= 3
%e F(M(1))= 5
%e F(M(2))= 257
%e F(M(3))= 340282366920938463463374607431768211457
%o (PARI) for(x=0,4,print( ( 2^(2^(2^x-1))+1 )))
%K nonn
%O 0,1
%A _Jorge Coveiro_, Dec 24 2004
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