|
|
A100882
|
|
Number of partitions of n in which the sequence of frequencies of the summands is nonincreasing.
|
|
21
|
|
|
1, 1, 2, 3, 4, 5, 8, 8, 12, 14, 18, 21, 29, 29, 40, 47, 56, 62, 83, 86, 111, 124, 146, 166, 207, 217, 267, 300, 352, 389, 471, 505, 604, 668, 772, 860, 1015, 1085, 1279, 1419, 1622, 1780, 2072, 2242, 2595, 2858, 3231, 3563, 4092, 4421, 5057, 5557, 6250
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
0,3
|
|
LINKS
|
|
|
EXAMPLE
|
a(4) = 4 because in each of the partitions 4, 3+1, 2+2, 1+1+1+1, the frequencies of the summands is nonincreasing as the summands decrease. The partition 2+1+1 is not counted because 2 is used once, but 1 is used twice.
|
|
MAPLE
|
b:= proc(n, i, t) option remember;
if n<0 then 0
elif n=0 then 1
elif i=1 then `if`(n<=t, 1, 0)
elif i=0 then 0
else b(n, i-1, t)
+add(b(n-i*j, i-1, j), j=1..min(t, floor(n/i)))
fi
end:
a:= n-> b(n, n, n):
|
|
MATHEMATICA
|
b[n_, i_, t_] := b[n, i, t] = Which[n<0, 0, n == 0, 1, i == 1, If[n <= t, 1, 0], i == 0, 0, True, b[n, i-1, t] + Sum[b[n-i*j, i-1, j], {j, 1, Min[t, Floor[n/i]]}]]; a[n_] := b[n, n, n]; Table[a[n], {n, 0, 60}] (* Jean-François Alcover, Oct 26 2015, after Alois P. Heinz *)
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
|
|
EXTENSIONS
|
|
|
STATUS
|
approved
|
|
|
|