%I #3 Mar 30 2012 18:59:02
%S 1,6,48,288,2400,14400,115200,691200,5764800,34588800,276710400,
%T 1660262400,13835520000,83013120000,664104960000,3984629760000,
%U 33232930569600,199397583417600,1595180667340800,9571084004044800
%N Inverse modulo 2 binomial transform of 7^n.
%C 7^n may be retrieved as sum{k=0..n, mod(binomial(n,k),2)A100740(k)}.
%F a(n)=sum{k=0..n, (-1)^A010060(n-k)*mod(binomial(n, k), 2)7^k}.
%K easy,nonn
%O 0,2
%A _Paul Barry_, Dec 06 2004