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Inverse modulo 2 binomial transform of 7^n.
1

%I #3 Mar 30 2012 18:59:02

%S 1,6,48,288,2400,14400,115200,691200,5764800,34588800,276710400,

%T 1660262400,13835520000,83013120000,664104960000,3984629760000,

%U 33232930569600,199397583417600,1595180667340800,9571084004044800

%N Inverse modulo 2 binomial transform of 7^n.

%C 7^n may be retrieved as sum{k=0..n, mod(binomial(n,k),2)A100740(k)}.

%F a(n)=sum{k=0..n, (-1)^A010060(n-k)*mod(binomial(n, k), 2)7^k}.

%K easy,nonn

%O 0,2

%A _Paul Barry_, Dec 06 2004