%I #3 Mar 30 2012 18:59:02
%S 1,5,35,175,1295,6475,45325,226625,1679615,8398075,58786525,293932625,
%T 2175101425,10875507125,76128549875,380642749375,2821109907455,
%U 14105549537275,98738846760925,493694233804625,3653337330154225
%N Inverse modulo 2 binomial transform of 6^n.
%C 6^n may be retrieved as sum{k=0..n, mod(binomial(n,k),2)A100739(k)}.
%F a(n)=sum{k=0..n, (-1)^A010060(n-k)*mod(binomial(n, k), 2)6^k}.
%K easy,nonn
%O 0,2
%A _Paul Barry_, Dec 06 2004