|
%I #4 Mar 02 2018 14:24:56
%S 256,262144,1125899906842624,316912650057057350374175801344,
%T 7067388259113537318333190002971674063309935587502475832486424805170479104
%N 4^(p^2) where p is prime.
%e 4^(2^2) = 256
%t 4^Prime[Range[5]]^2 (* _Harvey P. Dale_, Mar 02 2018 *)
%K nonn
%O 1,1
%A _Parthasarathy Nambi_, Dec 02 2004
| 