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a(n) = A100092(n^2+n+1).
2

%I #6 Aug 10 2021 11:04:43

%S 1,2,4,11,28,65,147,321,678,1382,2738,5289,9985,18452,33455,59616,

%T 104556,180690,308058,518648,863037,1420480,2314170,3734063,5970888,

%U 9466452,14887746,23235296,36000876,55395893,84680624,128636339,194239572

%N a(n) = A100092(n^2+n+1).

%H S. Kurz, <a href="http://www.mathe2.uni-bayreuth.de/sascha/papers/extremal_polyominoes_paper1_2.pdf">Counting polyominoes with minimum perimeter</a>, submitted to Ars Combinatoria

%Y Cf. A100092, A100093.

%K nonn

%O 0,2

%A _Sascha Kurz_, Nov 03 2004

%E a(0) prepended by _Jianing Song_, Aug 10 2021