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Positions of occurrences of the natural numbers as fourth subsequence in A100035.
16

%I #7 Apr 30 2014 01:30:10

%S 22,35,52,73,98,127,160,197,238,283,332,385,442,503,568,637,710,787,

%T 868,953,1042,1135,1232,1333,1438,1547,1660,1777,1898,2023,2152,2285,

%U 2422,2563,2708,2857,3010,3167,3328,3493,3662,3835,4012,4193,4378,4567,4760

%N Positions of occurrences of the natural numbers as fourth subsequence in A100035.

%C n>1: A100035(a(n))=n and A100035(m)<>n for a(n-1)<=m<a(n);

%C A100036(n) < A100037(n) < A100038(n) < a(n).

%F 2n^2 + 7n + 13 (conjectured). - _Ralf Stephan_, May 15 2007

%e First terms (10=A,11=B,12=C) of A100035(a(n)):

%e .....................1............2................3....

%e 1231435425165764736271879869584938291A9BA8B7A6B5A4B3A2B1;

%e a(1) = A084849(4) = 22, A100035(22) = 1;

%e a(2) = A014107(4) = 35, A100035(35) = 2;

%e a(3) = A033537(5) = 52, A100035(52) = 3;

%e a(4) = A100040(6) = 73, A100035(73) = 4;

%e a(5) = A100041(7) = 98, A100035(98) = 5.

%K nonn

%O 1,1

%A _Reinhard Zumkeller_, Oct 31 2004