OFFSET
1,2
COMMENTS
Agrees with A097419 for n>1.
The next term (a(9)) has 136 digits. - Harvey P. Dale, Nov 24 2024
LINKS
Eric Weisstein's World of Mathematics, Hexagonal Number.
FORMULA
a(n) = b(n) for n<=2, a(n) = b(a(n-1)) for n>2, where b(n) = A000384(n) = n*(2*n-1), the hexagonal numbers.
a(1) = 1, a(2) = 6, a(n) = 2*a(n-1)^2 - a(n-1) for n>2.
Let H(n) = n*(2*n-1) = the n-th hexagonal number. Define A(n, k) recursively by A(1, k) = H(k), A(n, k) = A(1, A(n-1, k)) for n>1. Then a(1) = A(1, 1), a(n) = A(n-1, 2) for n>1.
EXAMPLE
a(4) = b(a(3)) = b(b(a(2))) = b(b(b(2))) = b(b(6)) = b(66) = 8646, where b(n) = A000384(n).
MATHEMATICA
Join[{1}, NestList[PolygonalNumber[6, #]&, 6, 6]] (* Harvey P. Dale, Nov 24 2024 *)
PROG
(PARI)
{hexagonal(n) = n*(2*n-1)}
{a(n) = if(n<=2, hexagonal(n), hexagonal(a(n-1)))} \\ Klaus Brockhaus, Jan 10 2007
CROSSREFS
KEYWORD
nonn,changed
AUTHOR
Jonathan Vos Post, Nov 14 2004
EXTENSIONS
Edited by Klaus Brockhaus, Jan 10 2007
STATUS
approved