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A puzzle: reverse digits of n^2 + 10.
1

%I #6 Feb 27 2024 13:58:07

%S 10,11,41,91,62,53,64,95,47,19,11,131,451,971,602,532,662,992,433,173,

%T 14,154,494,935,685,536,686,937,497,158,19,179,4301,9901,6611,5321,

%U 6031,9731,4541,1351,161,1961,4771,9581,6491,5302,6212,9122,4132,1142,152

%N A puzzle: reverse digits of n^2 + 10.

%C The first term should really be 1 (cf. A097991, which gives a better version).

%t Do[Print[FromDigits[Reverse[IntegerDigits[n^2 + 10]]]], {n, 0, 50}] (Poff)

%t Join[{10},IntegerReverse[Range[50]^2+10]] (* _Harvey P. Dale_, Feb 27 2024 *)

%K nonn,base,easy

%O 0,1

%A _N. J. A. Sloane_, following a suggestion of Jacek Kolodziejczyk (zwi(AT)infogenia.pl), Sep 07 2004

%E More terms from Tracy Poff (tracy.poff(AT)gmail.com), Apr 15 2005