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%I #4 Oct 01 2013 17:58:02
%S 0,0,1,1,1,2,2,2,2,3,3,3,3,3,3,4,4,4,4,4,4,5,5,5,5,5,5,5,5,5,6,6,6,6,
%T 6,6,7,7,7,7,7,7,7,7,7,7,8,8,8,8,8,8,8,8,9,9,9,9,9,9,9,9,9,9,9,10,10,
%U 10,10,10,10,10,10,10,10,11,11,11,11,11,11,11,11,11,11,11,11,12,12,12,12
%N Integer part of the radii of circles with prime areas.
%F Radius = floor(sqrt(Area/Pi)).
%e If A = 5. floor(sqrt(5/Pi)) = 1, the third entry.
%o (PARI) f(n) = forprime(x=1,n,print1(floor(sqrt(x/Pi))","))
%K nonn
%O 2,6
%A _Cino Hilliard_, Aug 22 2004