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A097388 2n-th derivative of the Gaussian exp(-x^2) evaluated at x=0. 3

%I #40 Feb 06 2021 22:37:07

%S 1,-2,12,-120,1680,-30240,665280,-17297280,518918400,-17643225600,

%T 670442572800,-28158588057600,1295295050649600,-64764752532480000,

%U 3497296636753920000,-202843204931727360000,12576278705767096320000

%N 2n-th derivative of the Gaussian exp(-x^2) evaluated at x=0.

%C H_n(0) := n-th derivative of exp(-x^2) at x=0. H_(2*n + 1)(0) = 0 if n >= 0. - _Michael Somos_, Jan 24 2014

%C Self-convolution gives A076729(n)*(-1)^n. - _Vladimir Reshetnikov_, Oct 11 2016

%F E.g.f.: Sum_{k>=0} a(k) * x^(2*k) / (2*k)! = exp(-x^2).

%F a(n) = (-1)^n *(2*n)! / n!.

%F G.f.: 1/U(0) where U(k) = 1 + x*(2*k+2)/U(k+1); (continued fraction, 1-step). - _Sergei N. Gladkovskii_, Nov 14 2012

%F G.f.: 1/Q(0), where Q(k) = 1 - x*(8*k+2) + x*(8*k+4)/(1 - x*(8*k+6) + x*(8*k+8)/Q(k+1)); (continued fraction). - _Sergei N. Gladkovskii_, May 18 2013

%F a(n) = (-1)^n * A001813(n).

%F G.f. = 1 / (1 + 2*x / (1 + 4*x / (1 + 6*x / ... ))). - _Michael Somos_, Jan 24 2014

%F a(n) ~ (-1)^n*2^(2*n+1/2)*n^n/exp(n). - _Ilya Gutkovskiy_, Oct 11 2016

%F Sum_{n>=0} 1/a(n) = 1 - sqrt(Pi)*erfi(1/2)/(2*exp(1/4)). - _Amiram Eldar_, Nov 12 2020

%F From _Nikolaos Pantelidis_, Jan 08 2021: (Start)

%F G.f.: 1/G(1), where G(n) = 1+(8*n-6)*x-8*n*(2*n-1)*x^2/G(n+1); (Jacobi continued fraction)

%F G.f.: 1/(1 + 2*x - 8*x^2/(1 + 10*x - 48*x^2/(1 + 18*x - 120*x^2/(1 + 26*x - 224*x^2/(1 + 34*x - 360*x^2/(1+ 42*x - 448*x^2/(1+ 50*x - 648*x^2/( ...)))))))) (Jacobi continued fraction).

%F (End)

%e exp(-x^2) = 1 - x^2 + x^4/4 - x^6/6 + ..., (d/dx)^4 exp(-x^2) = 12 - 60x^2 + ... so a(2)=12.

%e G.f. = 1 - 2*x + 12*x^2 - 120*x^3 + 1680*x^4 - 30240*x^5 + 665280*x^6 + ...

%t a[ n_] := If[ n < 0, 0, HermiteH[ 2 n, 0]]; (* _Michael Somos_, Jan 24 2014 *)

%o (PARI) {a(n) = if( n<0, 0, (-1)^n * (2*n)! / n!)};

%Y Cf. A001813, A076729.

%K sign

%O 0,2

%A _Michael Somos_, Aug 12 2004

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Last modified September 15 00:47 EDT 2024. Contains 375929 sequences. (Running on oeis4.)