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A096549
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Least exponent k such that the lowest n digits in the decimal representation of 2^k are even.
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1
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1, 6, 10, 11, 19, 43, 50, 50, 71, 71, 523, 590, 590, 12106, 12106, 12106, 12106, 56590, 505206, 1570511, 1570511, 4033966, 4033966, 9525771, 24045606, 24045606, 57862019, 183002599, 183002599, 877875719, 877875719, 877875719, 3789535319
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OFFSET
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1,2
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COMMENTS
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This problem was discussed in a thread "Power of 2 with all even digits?" in the newsgroup sci.math (Jun 25 2004) with contributions from Edwin Clark, James Waldby, Bertram Felgenhauer, Richard Tobin, Oskar Lanzi III and others.
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LINKS
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EXAMPLE
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a(5)=19 because 2^19=524288 is the smallest power of 2 that has a decimal representation ending in 5 even digits.
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CROSSREFS
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KEYWORD
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base,nonn
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AUTHOR
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EXTENSIONS
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a(21) - a(35) from Richard Tobin (richard(AT)cogsci.ed.ac.uk), Jun 29 2004
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STATUS
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approved
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