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a(1)=a(2)=1, a(n) = (a(n-2)+p(n-2)) * (a(n-1)+p(n-1)) for n > 2 where p(i) is the i-th prime number.
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%I #3 Mar 31 2012 14:11:11

%S 1,1,12,68,1275,96450,124051418,11966373574405,1484445813653376498440,

%T 17763433157166097952069326452110312,

%U 26368853986266794807407924573581272433758950459492905883

%N a(1)=a(2)=1, a(n) = (a(n-2)+p(n-2)) * (a(n-1)+p(n-1)) for n > 2 where p(i) is the i-th prime number.

%C The terms have an interesting factorization pattern, often sharing factors.

%K nonn

%O 1,3

%A _Gerald McGarvey_, Aug 08 2004