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a(n) = floor((Pi/sqrt(2))^n).
1

%I #15 Sep 08 2022 08:45:13

%S 1,2,4,10,24,54,120,266,593,1317,2926,6501,14441,32081,71266,158315,

%T 351688,781255,1735512,3855339,8564410,19025337,42263673,93886277,

%U 208562871,463310210,1029216515,2286344247,5078979923,11282656623

%N a(n) = floor((Pi/sqrt(2))^n).

%H Vincenzo Librandi, <a href="/A095214/b095214.txt">Table of n, a(n) for n = 0..1000</a>

%t Floor[(Pi/Sqrt[2])^Range[0,30]] (* _Harvey P. Dale_, May 12 2014 *)

%o (PARI) vector(30, n, n--; floor((Pi/sqrt(2))^n)) \\ _G. C. Greubel_, Sep 27 2018

%o (Magma) R:= RealField(20); [Floor((Pi(R)/Sqrt(2))^n): n in [0..30]]; // _G. C. Greubel_, Sep 27 2018

%Y Cf. A247719 (Pi/sqrt(2)).

%K nonn,easy

%O 0,2

%A _Jason Earls_, Jun 22 2004