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%I #4 Jan 01 2024 18:38:18
%S 1,1,1,1,1,1,1,1,1,1,1,2,1,1,1,3,1,2,3,2,2,1,2,2,3,1,3,2,1,2,2,4,1,3,
%T 4,3,1,2,3,4,4,2,3,4,3,3,4,3,5,3,6,3,5,4,3,4,2,1,2,3,2,3,2,5,5,4,3,4,
%U 6,5,2,5,3,4,1,4,2,2,3,4
%N Number of distinct prime factors of A095134(n).
%F a(n) = A001221(A095134(n)). - _Wesley Ivan Hurt_, Jan 01 2024
%t PrimeFactors[n_] := Flatten[ Table[ #[[1]], {1} ] & /@ FactorInteger[n]]; f[n_] := Product[ Prime[i], {i, 2, n, 2}] + Product[ Prime[i], {i, 1, n, 2}]; f[1] = 2; Table[ Length[ PrimeFactors[ f[n]]], {n, 80}]
%Y Cf. A001221, A095134.
%K nonn
%O 1,12
%A _Robert G. Wilson v_, May 27 2004
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