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a(n) = floor(9^n/2^n).
1

%I #13 Sep 08 2022 08:45:13

%S 1,4,20,91,410,1845,8303,37366,168151,756680,3405062,15322783,

%T 68952523,310286355,1396288601,6283298708,28274844190,127236798856,

%U 572565594852,2576545176835,11594453295761,52175039830928,234787679239180

%N a(n) = floor(9^n/2^n).

%H Vincenzo Librandi, <a href="/A094971/b094971.txt">Table of n, a(n) for n = 0..900</a>

%t Table[ Floor[(9/2)^n], {n, 0, 30}]

%o (Magma) [Floor(9^n / 2^n): n in [0..30]]; // _Vincenzo Librandi_, Sep 08 2011

%o (PARI) a(n)=9^n>>n \\ _Charles R Greathouse IV_, Feb 04 2016

%Y Cf. A002379, A094969-A094999.

%K nonn,easy

%O 0,2

%A _Robert G. Wilson v_, May 26 2004