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a(n) = floor(5^n/2^n).
33

%I #28 Sep 08 2022 08:45:13

%S 1,2,6,15,39,97,244,610,1525,3814,9536,23841,59604,149011,372529,

%T 931322,2328306,5820766,14551915,36379788,90949470,227373675,

%U 568434188,1421085471,3552713678,8881784197,22204460492,55511151231,138777878078,346944695195,867361737988

%N a(n) = floor(5^n/2^n).

%H Vincenzo Librandi, <a href="/A094969/b094969.txt">Table of n, a(n) for n = 0..1000</a>

%p A094969:=n->floor(5^n/2^n): seq(A094969(n), n=0..40); # _Wesley Ivan Hurt_, Feb 22 2017

%t Table[ Floor[(5/2)^n], {n, 0, 30}]

%t Floor[(5/2)^Range[0,30]] (* _Harvey P. Dale_, Jul 16 2012 *)

%o (Magma) [Floor(5^n / 2^n): n in [0..30]]; // _Vincenzo Librandi_, Sep 08 2011

%o (PARI) a(n)=5^n>>n \\ _Charles R Greathouse IV_, Sep 08 2011

%o (Maxima) A094969(n):=floor(5^n/2^n)$ makelist(A094969(n),n,0,30); /* _Martin Ettl_, Oct 25 2012 */

%Y Cf. A002379, A094970-A094999.

%K nonn,easy

%O 0,2

%A _Robert G. Wilson v_, May 26 2004