|
%I #5 Aug 21 2013 20:15:06
%S 0,1,10,101,1011,10110,101101,1011011,10110111,101101110,1011011101,
%T 10110111011,101101110111,1011011101111,10110111011110,
%U 101101110111101,1011011101111011,10110111011110111,101101110111101111
%N Initial n terms of A023532(n) taken as digits.
%F Convolution of A023532(n) and 10^n:
%F a(n)=sum{k=0..n, A023532(n)*10^(n-k)}
%Y Cf. A094946.
%K easy,nonn,base
%O 0,3
%A _Paul Barry_, May 25 2004
%E Name changed by _Franklin T. Adams-Watters_, Aug 21 2013
|
